What are the solutions to the equation 0.2x^2-0.5x-7=0 ?

The solutions to the equation 0.2x^2-0.5x-7=0 are x=(5+3sqrt(65))/4 ,x=(5-3sqrt(65))/4

Find the zeros of 0.2x^2-0.5x-7=0

The zeros of 0.2x^2-0.5x-7=0 are x=(5+3sqrt(65))/4 ,x=(5-3sqrt(65))/4

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0.2 x^{2} - 0.5 x - 7 = 0

x = \frac{5 + 3 65}{4}, x = \frac{5 - 3 65}{4}

Solution steps

0.2 x^{2} - 0.5 x - 7 = 0

Multiply both sides by

10

2 x^{2} - 5 x - 70 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 70 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 70) = 365

x_{1, 2} = \frac{- ( - 5 ) \pm 3 65}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3 65}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 3 65}{2 \cdot 2}

x = \frac{- ( - 5 ) + 3 65}{2 \cdot 2} : \frac{5 + 3 65}{4}

x = \frac{- ( - 5 ) - 3 65}{2 \cdot 2} : \frac{5 - 3 65}{4}

The solutions to the quadratic equation are:

x = \frac{5 + 3 65}{4}, x = \frac{5 - 3 65}{4}

13 x - 36 = x^{2}

x, 2 x^{2} + y^{2} = C

4 x^{2} + 3 x + 22 = 0

x^{2} - a x - 2 a = 0

x^{2} - 25 x + 475 = 0

What are the solutions to the equation 0.2x^2-0.5x-7=0 ?
The solutions to the equation 0.2x^2-0.5x-7=0 are x=(5+3sqrt(65))/4 ,x=(5-3sqrt(65))/4
Find the zeros of 0.2x^2-0.5x-7=0
The zeros of 0.2x^2-0.5x-7=0 are x=(5+3sqrt(65))/4 ,x=(5-3sqrt(65))/4