What are the solutions to the equation -x^2-x=-4 ?

The solutions to the equation -x^2-x=-4 are x=-(1+sqrt(17))/2 ,x=(sqrt(17)-1)/2

Find the zeros of -x^2-x=-4

The zeros of -x^2-x=-4 are x=-(1+sqrt(17))/2 ,x=(sqrt(17)-1)/2

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- x^{2} - x = - 4

x = - \frac{1 + 17}{2}, x = \frac{17 - 1}{2}

Decimal Notation

x = - 2.56155 \dots, x = 1.56155 \dots

Solution steps

- x^{2} - x = - 4

Move

4

to the left side

- x^{2} - x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 4 = 17

x_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 17}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 17}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 17}{2 ( - 1 )} : - \frac{1 + 17}{2}

x = \frac{- ( - 1 ) - 17}{2 ( - 1 )} : \frac{17 - 1}{2}

The solutions to the quadratic equation are:

x = - \frac{1 + 17}{2}, x = \frac{17 - 1}{2}

x (x + 7) = 14

(2 x + 1)^{2} - (x + 2) = x (x + 2) + 3

(x + 8)^{2} = - x - 2

3 x^{2} + 7 x - 6 = 0

(3 x + 2) (2 x - 5) = (4 x - 1) (5 x + 6)

What are the solutions to the equation -x^2-x=-4 ?
The solutions to the equation -x^2-x=-4 are x=-(1+sqrt(17))/2 ,x=(sqrt(17)-1)/2
Find the zeros of -x^2-x=-4
The zeros of -x^2-x=-4 are x=-(1+sqrt(17))/2 ,x=(sqrt(17)-1)/2