What are the solutions to the equation 30(p^2-1)=11p ?

The solutions to the equation 30(p^2-1)=11p are p= 6/5 ,p=-5/6

Find the zeros of 30(p^2-1)=11p

The zeros of 30(p^2-1)=11p are p= 6/5 ,p=-5/6

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30 (p^{2} - 1) = 11 p

p = \frac{6}{5}, p = - \frac{5}{6}

Decimal Notation

p = 1.2, p = - 0.83333 \dots

Solution steps

30 (p^{2} - 1) = 11 p

Expand

30 (p^{2} - 1) : 30 p^{2} - 30

30 p^{2} - 30 = 11 p

Move

11 p

to the left side

30 p^{2} - 30 - 11 p = 0

Write in the standard form

a x^{2} + b x + c = 0

30 p^{2} - 11 p - 30 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 30 ( - 30 )}{2 \cdot 30}

(- 11)^{2} - 4 \cdot 30 (- 30) = 61

p_{1, 2} = \frac{- ( - 11 ) \pm 61}{2 \cdot 30}

Separate the solutions

p_{1} = \frac{- ( - 11 ) + 61}{2 \cdot 30}, p_{2} = \frac{- ( - 11 ) - 61}{2 \cdot 30}

p = \frac{- ( - 11 ) + 61}{2 \cdot 30} : \frac{6}{5}

p = \frac{- ( - 11 ) - 61}{2 \cdot 30} : - \frac{5}{6}

The solutions to the quadratic equation are:

p = \frac{6}{5}, p = - \frac{5}{6}

2 x^{2} = 10 x - 25

x^{2} - (k + 2) x + k + 1 = 0

x^{2} - 5 = 3 x

(x - 13)^{2} = 400

x^{2} - 3 x - 0.9 = 0

What are the solutions to the equation 30(p^2-1)=11p ?
The solutions to the equation 30(p^2-1)=11p are p= 6/5 ,p=-5/6
Find the zeros of 30(p^2-1)=11p
The zeros of 30(p^2-1)=11p are p= 6/5 ,p=-5/6