What are the solutions to the equation 3x(2x+9)=10x ?

The solutions to the equation 3x(2x+9)=10x are x=0,x=-17/6

Find the zeros of 3x(2x+9)=10x

The zeros of 3x(2x+9)=10x are x=0,x=-17/6

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3 x (2 x + 9) = 10 x

x = 0, x = - \frac{17}{6}

Decimal Notation

x = 0, x = - 2.83333 \dots

Solution steps

3 x (2 x + 9) = 10 x

Move

10 x

to the left side

3 x (2 x + 9) - 10 x = 0

Factor

3 x (2 x + 9) - 10 x : x (6 x + 17)

x (6 x + 17) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 6 x + 17 = 0

Solve

6 x + 17 = 0 : x = - \frac{17}{6}

The solutions to the quadratic equation are:

x = 0, x = - \frac{17}{6}

4 x^{2} - 11 x = 7

7 c^{2} = c + 6

4 c^{2} + c - 6 = 0

9 x + 28 = 9 x^{2}

11 x = 3 x^{2} - 9

What are the solutions to the equation 3x(2x+9)=10x ?
The solutions to the equation 3x(2x+9)=10x are x=0,x=-17/6
Find the zeros of 3x(2x+9)=10x
The zeros of 3x(2x+9)=10x are x=0,x=-17/6