What are the solutions to the equation 2d^2=8d+90 ?

The solutions to the equation 2d^2=8d+90 are d=9,d=-5

Find the zeros of 2d^2=8d+90

The zeros of 2d^2=8d+90 are d=9,d=-5

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2 d^{2} = 8 d + 90

d = 9, d = - 5

Solution steps

2 d^{2} = 8 d + 90

Move

90

to the left side

2 d^{2} - 90 = 8 d

Move

8 d

to the left side

2 d^{2} - 90 - 8 d = 0

Write in the standard form

a x^{2} + b x + c = 0

2 d^{2} - 8 d - 90 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 ( - 90 )}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 (- 90) = 28

d_{1, 2} = \frac{- ( - 8 ) \pm 28}{2 \cdot 2}

Separate the solutions

d_{1} = \frac{- ( - 8 ) + 28}{2 \cdot 2}, d_{2} = \frac{- ( - 8 ) - 28}{2 \cdot 2}

d = \frac{- ( - 8 ) + 28}{2 \cdot 2} : 9

d = \frac{- ( - 8 ) - 28}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

d = 9, d = - 5

2 x^{2} + 3 x - 16 = 4

v^{2} = 47

6 x^{2} = - x + 1

(x - 1)^{2} + 3 = 2 x + 1

64 = 80 t - 16 t^{2}

What are the solutions to the equation 2d^2=8d+90 ?
The solutions to the equation 2d^2=8d+90 are d=9,d=-5
Find the zeros of 2d^2=8d+90
The zeros of 2d^2=8d+90 are d=9,d=-5