What are the solutions to the equation (x-1)^2+3=2x+1 ?

The solutions to the equation (x-1)^2+3=2x+1 are x=3,x=1

Find the zeros of (x-1)^2+3=2x+1

The zeros of (x-1)^2+3=2x+1 are x=3,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 1)^{2} + 3 = 2 x + 1

x = 3, x = 1

Solution steps

(x - 1)^{2} + 3 = 2 x + 1

Expand

(x - 1)^{2} + 3 : x^{2} - 2 x + 4

x^{2} - 2 x + 4 = 2 x + 1

Move

1

to the left side

x^{2} - 2 x + 3 = 2 x

Move

2 x

to the left side

x^{2} - 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2}{2 \cdot 1} : 3

x = \frac{- ( - 4 ) - 2}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

64 = 80 t - 16 t^{2}

2 x^{2} + x = - 9

x^{2} + 9 b^{2} = 0, b \neq = 0

X^{2} + 5 X + 2 = - 4

- 4 x^{2} - 24 x - 40

What are the solutions to the equation (x-1)^2+3=2x+1 ?
The solutions to the equation (x-1)^2+3=2x+1 are x=3,x=1
Find the zeros of (x-1)^2+3=2x+1
The zeros of (x-1)^2+3=2x+1 are x=3,x=1