What are the solutions to the equation 6x^2=-x+1 ?

The solutions to the equation 6x^2=-x+1 are x= 1/3 ,x=-1/2

Find the zeros of 6x^2=-x+1

The zeros of 6x^2=-x+1 are x= 1/3 ,x=-1/2

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6 x^{2} = - x + 1

x = \frac{1}{3}, x = - \frac{1}{2}

Solution steps

6 x^{2} = - x + 1

Move

1

to the left side

6 x^{2} - 1 = - x

Move

x

to the left side

6 x^{2} - 1 + x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 1) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 6}, x_{2} = \frac{- 1 - 5}{2 \cdot 6}

x = \frac{- 1 + 5}{2 \cdot 6} : \frac{1}{3}

x = \frac{- 1 - 5}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{1}{2}

(x - 1)^{2} + 3 = 2 x + 1

64 = 80 t - 16 t^{2}

2 x^{2} + x = - 9

x^{2} + 9 b^{2} = 0, b \neq = 0

X^{2} + 5 X + 2 = - 4

What are the solutions to the equation 6x^2=-x+1 ?
The solutions to the equation 6x^2=-x+1 are x= 1/3 ,x=-1/2
Find the zeros of 6x^2=-x+1
The zeros of 6x^2=-x+1 are x= 1/3 ,x=-1/2