What are the solutions to the equation 2x^2+x=-9 ?

The solutions to the equation 2x^2+x=-9 are x=-1/4+i(sqrt(71))/4 ,x=-1/4-i(sqrt(71))/4

Find the zeros of 2x^2+x=-9

The zeros of 2x^2+x=-9 are x=-1/4+i(sqrt(71))/4 ,x=-1/4-i(sqrt(71))/4

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2 x^{2} + x = - 9

x = - \frac{1}{4} + i \frac{71}{4}, x = - \frac{1}{4} - i \frac{71}{4}

Solution steps

2 x^{2} + x = - 9

Move

9

to the left side

2 x^{2} + x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 \cdot 9}{2 \cdot 2}

Simplify

1^{2} - 4 \cdot 2 \cdot 9 : 71 i

x_{1, 2} = \frac{- 1 \pm 71 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 71 i}{2 \cdot 2}, x_{2} = \frac{- 1 - 71 i}{2 \cdot 2}

x = \frac{- 1 + 71 i}{2 \cdot 2} : - \frac{1}{4} + i \frac{71}{4}

x = \frac{- 1 - 71 i}{2 \cdot 2} : - \frac{1}{4} - i \frac{71}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4} + i \frac{71}{4}, x = - \frac{1}{4} - i \frac{71}{4}

x^{2} + 9 b^{2} = 0, b \neq = 0

X^{2} + 5 X + 2 = - 4

- 4 x^{2} - 24 x - 40

3 x^{2} - 18 x + 17

x, x^{2} = x y

What are the solutions to the equation 2x^2+x=-9 ?
The solutions to the equation 2x^2+x=-9 are x=-1/4+i(sqrt(71))/4 ,x=-1/4-i(sqrt(71))/4
Find the zeros of 2x^2+x=-9
The zeros of 2x^2+x=-9 are x=-1/4+i(sqrt(71))/4 ,x=-1/4-i(sqrt(71))/4