What are the solutions to the equation x^2+9b^2=0,b\ne 0 ?

The solutions to the equation x^2+9b^2=0,b\ne 0 are x=3sqrt(-b^2),x=-3sqrt(-b^2)

Find the zeros of x^2+9b^2=0,b\ne 0

The zeros of x^2+9b^2=0,b\ne 0 are x=3sqrt(-b^2),x=-3sqrt(-b^2)

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x^{2} + 9 b^{2} = 0, b \neq = 0

x = 3 - b^{2}, x = - 3 - b^{2}

Solution steps

x^{2} + 9 b^{2} = 0, b \neq = 0

Move

9 b^{2}

to the right side

x^{2} = - 9 b^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 9 b^{2}, x = - - 9 b^{2}

Simplify

- 9 b^{2} : 3 - b^{2}

Simplify

- - 9 b^{2} : - 3 - b^{2}

x = 3 - b^{2}, x = - 3 - b^{2}

X^{2} + 5 X + 2 = - 4

- 4 x^{2} - 24 x - 40

3 x^{2} - 18 x + 17

x, x^{2} = x y

49 - (2 x)^{2} = 0

What are the solutions to the equation x^2+9b^2=0,b\ne 0 ?
The solutions to the equation x^2+9b^2=0,b\ne 0 are x=3sqrt(-b^2),x=-3sqrt(-b^2)
Find the zeros of x^2+9b^2=0,b\ne 0
The zeros of x^2+9b^2=0,b\ne 0 are x=3sqrt(-b^2),x=-3sqrt(-b^2)