What are the solutions to the equation x^2+4=2x^2-12 ?

The solutions to the equation x^2+4=2x^2-12 are x=4,x=-4

Find the zeros of x^2+4=2x^2-12

The zeros of x^2+4=2x^2-12 are x=4,x=-4

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x^{2} + 4 = 2 x^{2} - 12

x = 4, x = - 4

Solution steps

x^{2} + 4 = 2 x^{2} - 12

Move

4

to the right side

x^{2} = 2 x^{2} - 16

Move

2 x^{2}

to the left side

- x^{2} = - 16

Divide both sides by

- 1

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

3 x^{2} - 3 = 45

x^{2} - 2 = 10

5 x^{2} - 8 = 12 x

x^{2} - 6 x - 22 = 0

10 x - 25 - x^{2} = 0

What are the solutions to the equation x^2+4=2x^2-12 ?
The solutions to the equation x^2+4=2x^2-12 are x=4,x=-4
Find the zeros of x^2+4=2x^2-12
The zeros of x^2+4=2x^2-12 are x=4,x=-4