What are the solutions to the equation x^2-6x-22=0 ?

The solutions to the equation x^2-6x-22=0 are x=3+sqrt(31),x=3-sqrt(31)

Find the zeros of x^2-6x-22=0

The zeros of x^2-6x-22=0 are x=3+sqrt(31),x=3-sqrt(31)

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x^{2} - 6 x - 22 = 0

x = 3 + 31, x = 3 - 31

Solution steps

x^{2} - 6 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 22 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 22) = 231

x_{1, 2} = \frac{- ( - 6 ) \pm 2 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 31}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 31}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 31}{2 \cdot 1} : 3 + 31

x = \frac{- ( - 6 ) - 2 31}{2 \cdot 1} : 3 - 31

The solutions to the quadratic equation are:

x = 3 + 31, x = 3 - 31

10 x - 25 - x^{2} = 0

\frac{x ^{2}}{18} = \frac{x}{9}

6 (5 + x)^{2} - 42 = 0

- 28 a - 14 a^{2} = 0

x^{2} - 14 = x - 2

What are the solutions to the equation x^2-6x-22=0 ?
The solutions to the equation x^2-6x-22=0 are x=3+sqrt(31),x=3-sqrt(31)
Find the zeros of x^2-6x-22=0
The zeros of x^2-6x-22=0 are x=3+sqrt(31),x=3-sqrt(31)