What are the solutions to the equation 5x^2-8=12x ?

The solutions to the equation 5x^2-8=12x are x=(2(3+sqrt(19)))/5 ,x=(2(3-sqrt(19)))/5

Find the zeros of 5x^2-8=12x

The zeros of 5x^2-8=12x are x=(2(3+sqrt(19)))/5 ,x=(2(3-sqrt(19)))/5

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5 x^{2} - 8 = 12 x

x = \frac{2 ( 3 + 19 )}{5}, x = \frac{2 ( 3 - 19 )}{5}

Solution steps

5 x^{2} - 8 = 12 x

Move

12 x

to the left side

5 x^{2} - 8 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 12 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 5 ( - 8 )}{2 \cdot 5}

(- 12)^{2} - 4 \cdot 5 (- 8) = 419

x_{1, 2} = \frac{- ( - 12 ) \pm 4 19}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 19}{2 \cdot 5}, x_{2} = \frac{- ( - 12 ) - 4 19}{2 \cdot 5}

x = \frac{- ( - 12 ) + 4 19}{2 \cdot 5} : \frac{2 ( 3 + 19 )}{5}

x = \frac{- ( - 12 ) - 4 19}{2 \cdot 5} : \frac{2 ( 3 - 19 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 3 + 19 )}{5}, x = \frac{2 ( 3 - 19 )}{5}

x^{2} - 6 x - 22 = 0

10 x - 25 - x^{2} = 0

\frac{x ^{2}}{18} = \frac{x}{9}

6 (5 + x)^{2} - 42 = 0

- 28 a - 14 a^{2} = 0

What are the solutions to the equation 5x^2-8=12x ?
The solutions to the equation 5x^2-8=12x are x=(2(3+sqrt(19)))/5 ,x=(2(3-sqrt(19)))/5
Find the zeros of 5x^2-8=12x
The zeros of 5x^2-8=12x are x=(2(3+sqrt(19)))/5 ,x=(2(3-sqrt(19)))/5