What are the solutions to the equation -28a-14a^2=0 ?

The solutions to the equation -28a-14a^2=0 are a=-2,a=0

Find the zeros of -28a-14a^2=0

The zeros of -28a-14a^2=0 are a=-2,a=0

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- 28 a - 14 a^{2} = 0

a = - 2, a = 0

Solution steps

- 28 a - 14 a^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 14 a^{2} - 28 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 ( - 14 ) \cdot 0}{2 ( - 14 )}

(- 28)^{2} - 4 (- 14) \cdot 0 = 28

a_{1, 2} = \frac{- ( - 28 ) \pm 28}{2 ( - 14 )}

Separate the solutions

a_{1} = \frac{- ( - 28 ) + 28}{2 ( - 14 )}, a_{2} = \frac{- ( - 28 ) - 28}{2 ( - 14 )}

a = \frac{- ( - 28 ) + 28}{2 ( - 14 )} : - 2

a = \frac{- ( - 28 ) - 28}{2 ( - 14 )} : 0

The solutions to the quadratic equation are:

a = - 2, a = 0

x^{2} - 14 = x - 2

8 x^{2} - (m - 1) x + (m - 7) = 0

5 x^{2} + 7 x - 4 = - 7 x - 1

x (2 x - 4) = (x - 2) (x - 2)

3 x^{2} - 1 = 3 - 2 x^{2}

What are the solutions to the equation -28a-14a^2=0 ?
The solutions to the equation -28a-14a^2=0 are a=-2,a=0
Find the zeros of -28a-14a^2=0
The zeros of -28a-14a^2=0 are a=-2,a=0