What are the solutions to the equation x^2-14=x-2 ?

The solutions to the equation x^2-14=x-2 are x=4,x=-3

Find the zeros of x^2-14=x-2

The zeros of x^2-14=x-2 are x=4,x=-3

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x^{2} - 14 = x - 2

x = 4, x = - 3

Solution steps

x^{2} - 14 = x - 2

Move

2

to the left side

x^{2} - 12 = x

Move

x

to the left side

x^{2} - 12 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 12) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 1}

x = \frac{- ( - 1 ) + 7}{2 \cdot 1} : 4

x = \frac{- ( - 1 ) - 7}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 4, x = - 3

8 x^{2} - (m - 1) x + (m - 7) = 0

5 x^{2} + 7 x - 4 = - 7 x - 1

x (2 x - 4) = (x - 2) (x - 2)

3 x^{2} - 1 = 3 - 2 x^{2}

(3 x + 2) (2 x - 1) = 0

What are the solutions to the equation x^2-14=x-2 ?
The solutions to the equation x^2-14=x-2 are x=4,x=-3
Find the zeros of x^2-14=x-2
The zeros of x^2-14=x-2 are x=4,x=-3