What are the solutions to the equation 5x^2-8x-24=0 ?

The solutions to the equation 5x^2-8x-24=0 are x=(2(2+sqrt(34)))/5 ,x=(2(2-sqrt(34)))/5

Find the zeros of 5x^2-8x-24=0

The zeros of 5x^2-8x-24=0 are x=(2(2+sqrt(34)))/5 ,x=(2(2-sqrt(34)))/5

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5 x^{2} - 8 x - 24 = 0

x = \frac{2 ( 2 + 34 )}{5}, x = \frac{2 ( 2 - 34 )}{5}

Decimal Notation

x = 3.13238 \dots, x = - 1.53238 \dots

Solution steps

5 x^{2} - 8 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 5 ( - 24 )}{2 \cdot 5}

(- 8)^{2} - 4 \cdot 5 (- 24) = 434

x_{1, 2} = \frac{- ( - 8 ) \pm 4 34}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 34}{2 \cdot 5}, x_{2} = \frac{- ( - 8 ) - 4 34}{2 \cdot 5}

x = \frac{- ( - 8 ) + 4 34}{2 \cdot 5} : \frac{2 ( 2 + 34 )}{5}

x = \frac{- ( - 8 ) - 4 34}{2 \cdot 5} : \frac{2 ( 2 - 34 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 2 + 34 )}{5}, x = \frac{2 ( 2 - 34 )}{5}

x (x + 5) = 12

x^{2} - 6 x - 160 = 0

x^{2} + 3 = 100

3 x^{2} - 72 = 2 x^{2} + 28

x, 2 x^{2} + 4 x + 1 = 0

What are the solutions to the equation 5x^2-8x-24=0 ?
The solutions to the equation 5x^2-8x-24=0 are x=(2(2+sqrt(34)))/5 ,x=(2(2-sqrt(34)))/5
Find the zeros of 5x^2-8x-24=0
The zeros of 5x^2-8x-24=0 are x=(2(2+sqrt(34)))/5 ,x=(2(2-sqrt(34)))/5