What are the solutions to the equation 6k^2+7k-11=5k^2 ?

The solutions to the equation 6k^2+7k-11=5k^2 are k=(-7+sqrt(93))/2 ,k=(-7-sqrt(93))/2

Find the zeros of 6k^2+7k-11=5k^2

The zeros of 6k^2+7k-11=5k^2 are k=(-7+sqrt(93))/2 ,k=(-7-sqrt(93))/2

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6 k^{2} + 7 k - 11 = 5 k^{2}

k = \frac{- 7 + 93}{2}, k = \frac{- 7 - 93}{2}

Decimal Notation

k = 1.32182 \dots, k = - 8.32182 \dots

Solution steps

6 k^{2} + 7 k - 11 = 5 k^{2}

Move

5 k^{2}

to the left side

k^{2} + 7 k - 11 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 11) = 93

k_{1, 2} = \frac{- 7 \pm 93}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 7 + 93}{2 \cdot 1}, k_{2} = \frac{- 7 - 93}{2 \cdot 1}

k = \frac{- 7 + 93}{2 \cdot 1} : \frac{- 7 + 93}{2}

k = \frac{- 7 - 93}{2 \cdot 1} : \frac{- 7 - 93}{2}

The solutions to the quadratic equation are:

k = \frac{- 7 + 93}{2}, k = \frac{- 7 - 93}{2}

x^{2} - 0.7 x + 0.1 = 0

m^{2} + 3 m = 4

(x + 4) (x - 2) = 4 x

(x + 7)^{2} = 289

5 x^{2} = 5 x + 6

What are the solutions to the equation 6k^2+7k-11=5k^2 ?
The solutions to the equation 6k^2+7k-11=5k^2 are k=(-7+sqrt(93))/2 ,k=(-7-sqrt(93))/2
Find the zeros of 6k^2+7k-11=5k^2
The zeros of 6k^2+7k-11=5k^2 are k=(-7+sqrt(93))/2 ,k=(-7-sqrt(93))/2