What are the solutions to the equation m^2+3m=4 ?

The solutions to the equation m^2+3m=4 are m=1,m=-4

Find the zeros of m^2+3m=4

The zeros of m^2+3m=4 are m=1,m=-4

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m^{2} + 3 m = 4

m = 1, m = - 4

Solution steps

m^{2} + 3 m = 4

Move

4

to the left side

m^{2} + 3 m - 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 4) = 5

m_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 3 + 5}{2 \cdot 1}, m_{2} = \frac{- 3 - 5}{2 \cdot 1}

m = \frac{- 3 + 5}{2 \cdot 1} : 1

m = \frac{- 3 - 5}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

m = 1, m = - 4

(x + 4) (x - 2) = 4 x

(x + 7)^{2} = 289

5 x^{2} = 5 x + 6

4 x^{2} + 72 x + 324 = 5 x^{2} + 48 x + 144

x, x^{2} = 3 x y - 6

What are the solutions to the equation m^2+3m=4 ?
The solutions to the equation m^2+3m=4 are m=1,m=-4
Find the zeros of m^2+3m=4
The zeros of m^2+3m=4 are m=1,m=-4