What are the solutions to the equation 8x^2-22x=21 ?

The solutions to the equation 8x^2-22x=21 are x= 7/2 ,x=-3/4

Find the zeros of 8x^2-22x=21

The zeros of 8x^2-22x=21 are x= 7/2 ,x=-3/4

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8 x^{2} - 22 x = 21

x = \frac{7}{2}, x = - \frac{3}{4}

Decimal Notation

x = 3.5, x = - 0.75

Solution steps

8 x^{2} - 22 x = 21

Move

21

to the left side

8 x^{2} - 22 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 8 ( - 21 )}{2 \cdot 8}

(- 22)^{2} - 4 \cdot 8 (- 21) = 34

x_{1, 2} = \frac{- ( - 22 ) \pm 34}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 34}{2 \cdot 8}, x_{2} = \frac{- ( - 22 ) - 34}{2 \cdot 8}

x = \frac{- ( - 22 ) + 34}{2 \cdot 8} : \frac{7}{2}

x = \frac{- ( - 22 ) - 34}{2 \cdot 8} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - \frac{3}{4}

(x + 7) (x - 7) = 3 x

10 = 6 t - t^{2}

2 m^{2} - 6 m + 10 = 3 m - m^{2} - 6

32 x^{2} - 8 x + 1 = 0

2 (x - 2) = 4 x - 3 (x + 2)^{2}

What are the solutions to the equation 8x^2-22x=21 ?
The solutions to the equation 8x^2-22x=21 are x= 7/2 ,x=-3/4
Find the zeros of 8x^2-22x=21
The zeros of 8x^2-22x=21 are x= 7/2 ,x=-3/4