What are the solutions to the equation 32x^2-8x+1=0 ?

The solutions to the equation 32x^2-8x+1=0 are x= 1/8+i 1/8 ,x= 1/8-i 1/8

Find the zeros of 32x^2-8x+1=0

The zeros of 32x^2-8x+1=0 are x= 1/8+i 1/8 ,x= 1/8-i 1/8

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32 x^{2} - 8 x + 1 = 0

x = \frac{1}{8} + i \frac{1}{8}, x = \frac{1}{8} - i \frac{1}{8}

Solution steps

32 x^{2} - 8 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 32 \cdot 1}{2 \cdot 32}

Simplify

(- 8)^{2} - 4 \cdot 32 \cdot 1 : 8 i

x_{1, 2} = \frac{- ( - 8 ) \pm 8 i}{2 \cdot 32}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8 i}{2 \cdot 32}, x_{2} = \frac{- ( - 8 ) - 8 i}{2 \cdot 32}

x = \frac{- ( - 8 ) + 8 i}{2 \cdot 32} : \frac{1}{8} + i \frac{1}{8}

x = \frac{- ( - 8 ) - 8 i}{2 \cdot 32} : \frac{1}{8} - i \frac{1}{8}

The solutions to the quadratic equation are:

x = \frac{1}{8} + i \frac{1}{8}, x = \frac{1}{8} - i \frac{1}{8}

2 (x - 2) = 4 x - 3 (x + 2)^{2}

0 = 3 x^{2} + 22 x - 16

3 e x^{2} - 4 e = 2 x

5 x^{2} + 2 x - 3 + 9 x = 0

D, g = b (a + D^{2})

What are the solutions to the equation 32x^2-8x+1=0 ?
The solutions to the equation 32x^2-8x+1=0 are x= 1/8+i 1/8 ,x= 1/8-i 1/8
Find the zeros of 32x^2-8x+1=0
The zeros of 32x^2-8x+1=0 are x= 1/8+i 1/8 ,x= 1/8-i 1/8