What are the solutions to the equation 10=6t-t^2 ?

The solutions to the equation 10=6t-t^2 are t=3-i,t=3+i

Find the zeros of 10=6t-t^2

The zeros of 10=6t-t^2 are t=3-i,t=3+i

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10 = 6 t - t^{2}

t = 3 - i, t = 3 + i

Solution steps

10 = 6 t - t^{2}

Switch sides

6 t - t^{2} = 10

Move

10

to the left side

6 t - t^{2} - 10 = 0

Write in the standard form

a x^{2} + b x + c = 0

- t^{2} + 6 t - 10 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 10 )}{2 ( - 1 )}

Simplify

6^{2} - 4 (- 1) (- 10) : 2 i

t_{1, 2} = \frac{- 6 \pm 2 i}{2 ( - 1 )}

Separate the solutions

t_{1} = \frac{- 6 + 2 i}{2 ( - 1 )}, t_{2} = \frac{- 6 - 2 i}{2 ( - 1 )}

t = \frac{- 6 + 2 i}{2 ( - 1 )} : 3 - i

t = \frac{- 6 - 2 i}{2 ( - 1 )} : 3 + i

The solutions to the quadratic equation are:

t = 3 - i, t = 3 + i

2 m^{2} - 6 m + 10 = 3 m - m^{2} - 6

32 x^{2} - 8 x + 1 = 0

2 (x - 2) = 4 x - 3 (x + 2)^{2}

0 = 3 x^{2} + 22 x - 16

3 e x^{2} - 4 e = 2 x

What are the solutions to the equation 10=6t-t^2 ?
The solutions to the equation 10=6t-t^2 are t=3-i,t=3+i
Find the zeros of 10=6t-t^2
The zeros of 10=6t-t^2 are t=3-i,t=3+i