What are the solutions to the equation 0=3x^2+22x-16 ?

The solutions to the equation 0=3x^2+22x-16 are x= 2/3 ,x=-8

Find the zeros of 0=3x^2+22x-16

The zeros of 0=3x^2+22x-16 are x= 2/3 ,x=-8

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0 = 3 x^{2} + 22 x - 16

x = \frac{2}{3}, x = - 8

Decimal Notation

x = 0.66666 \dots, x = - 8

Solution steps

0 = 3 x^{2} + 22 x - 16

Switch sides

3 x^{2} + 22 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

2 2^{2} - 4 \cdot 3 (- 16) = 26

x_{1, 2} = \frac{- 22 \pm 26}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 22 + 26}{2 \cdot 3}, x_{2} = \frac{- 22 - 26}{2 \cdot 3}

x = \frac{- 22 + 26}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 22 - 26}{2 \cdot 3} : - 8

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 8

3 e x^{2} - 4 e = 2 x

5 x^{2} + 2 x - 3 + 9 x = 0

D, g = b (a + D^{2})

4 (x + 3)^{2} + 2 = - 6

(x + 3) (x - 3) = x (4 x + 5)

What are the solutions to the equation 0=3x^2+22x-16 ?
The solutions to the equation 0=3x^2+22x-16 are x= 2/3 ,x=-8
Find the zeros of 0=3x^2+22x-16
The zeros of 0=3x^2+22x-16 are x= 2/3 ,x=-8