What are the solutions to the equation 10x^2+24x-130=0 ?

The solutions to the equation 10x^2+24x-130=0 are x= 13/5 ,x=-5

Find the zeros of 10x^2+24x-130=0

The zeros of 10x^2+24x-130=0 are x= 13/5 ,x=-5

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10 x^{2} + 24 x - 130 = 0

x = \frac{13}{5}, x = - 5

Decimal Notation

x = 2.6, x = - 5

Solution steps

10 x^{2} + 24 x - 130 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 10 ( - 130 )}{2 \cdot 10}

2 4^{2} - 4 \cdot 10 (- 130) = 76

x_{1, 2} = \frac{- 24 \pm 76}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 24 + 76}{2 \cdot 10}, x_{2} = \frac{- 24 - 76}{2 \cdot 10}

x = \frac{- 24 + 76}{2 \cdot 10} : \frac{13}{5}

x = \frac{- 24 - 76}{2 \cdot 10} : - 5

The solutions to the quadratic equation are:

x = \frac{13}{5}, x = - 5

x^{2} - 3 x + 4 = 2 x^{2} - 7 x - 8

(1 - x) (10 - x) - 9 = 0

(2 x + 4)^{2} = 5

49 x^{2} + 1 = 25

5 x^{2} - 30 x + 25 = 0

What are the solutions to the equation 10x^2+24x-130=0 ?
The solutions to the equation 10x^2+24x-130=0 are x= 13/5 ,x=-5
Find the zeros of 10x^2+24x-130=0
The zeros of 10x^2+24x-130=0 are x= 13/5 ,x=-5