What are the solutions to the equation x^2+21x+110=0 ?

The solutions to the equation x^2+21x+110=0 are x=-10,x=-11

Find the zeros of x^2+21x+110=0

The zeros of x^2+21x+110=0 are x=-10,x=-11

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x^{2} + 21 x + 110 = 0

x = - 10, x = - 11

Solution steps

x^{2} + 21 x + 110 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 1 \cdot 110}{2 \cdot 1}

2 1^{2} - 4 \cdot 1 \cdot 110 = 1

x_{1, 2} = \frac{- 21 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 21 + 1}{2 \cdot 1}, x_{2} = \frac{- 21 - 1}{2 \cdot 1}

x = \frac{- 21 + 1}{2 \cdot 1} : - 10

x = \frac{- 21 - 1}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = - 10, x = - 11

56 (p^{2} - 1) = 15 p

w^{2} - 4 w - 3 = 0

3 (x^{2} - 2 x + 4) = 0

- 3 (t - 1)^{2} + 12 = 0

- x^{2} + 9 = 25

What are the solutions to the equation x^2+21x+110=0 ?
The solutions to the equation x^2+21x+110=0 are x=-10,x=-11
Find the zeros of x^2+21x+110=0
The zeros of x^2+21x+110=0 are x=-10,x=-11