What are the solutions to the equation x^2-2x(x-2)+5=0 ?

The solutions to the equation x^2-2x(x-2)+5=0 are x=-1,x=5

Find the zeros of x^2-2x(x-2)+5=0

The zeros of x^2-2x(x-2)+5=0 are x=-1,x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 2 x (x - 2) + 5 = 0

x = - 1, x = 5

Solution steps

x^{2} - 2 x (x - 2) + 5 = 0

Expand

x^{2} - 2 x (x - 2) + 5 : - x^{2} + 4 x + 5

- x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 5}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 5 = 6

x_{1, 2} = \frac{- 4 \pm 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 6}{2 ( - 1 )}, x_{2} = \frac{- 4 - 6}{2 ( - 1 )}

x = \frac{- 4 + 6}{2 ( - 1 )} : - 1

x = \frac{- 4 - 6}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

x = - 1, x = 5

x, f (x + 1) = 3 x^{2} + 2 x - 4

6 x^{2} = 9 x + 5

(2 x + 3) (x - 3) = 0

4 x^{2} - x = 2 x^{2} + 7 x

3 x^{2} - 6 x + 15

What are the solutions to the equation x^2-2x(x-2)+5=0 ?
The solutions to the equation x^2-2x(x-2)+5=0 are x=-1,x=5
Find the zeros of x^2-2x(x-2)+5=0
The zeros of x^2-2x(x-2)+5=0 are x=-1,x=5