What are the solutions to the equation 2(z-1/9)^2=14 ?

The solutions to the equation 2(z-1/9)^2=14 are z=sqrt(7)+1/9 ,z=-sqrt(7)+1/9

Find the zeros of 2(z-1/9)^2=14

The zeros of 2(z-1/9)^2=14 are z=sqrt(7)+1/9 ,z=-sqrt(7)+1/9

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2 (z - \frac{1}{9})^{2} = 14

z = 7 + \frac{1}{9}, z = - 7 + \frac{1}{9}

Decimal Notation

z = 2.75686 \dots, z = - 2.53464 \dots

Solution steps

2 (z - \frac{1}{9})^{2} = 14

Divide both sides by

2

(z - \frac{1}{9})^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z - \frac{1}{9} = 7 : z = 7 + \frac{1}{9}

Solve

z - \frac{1}{9} = - 7 : z = - 7 + \frac{1}{9}

The solutions to the quadratic equation are:

z = 7 + \frac{1}{9}, z = - 7 + \frac{1}{9}

4 (u + 1)^{2} = 18

s^{2} - 30 s + 205 = - 46

75 d^{2} + 25 d = 0

4 p^{2} - 5 p - 1 = 4 p

y^{2} + 20 (y + 5) = 0

What are the solutions to the equation 2(z-1/9)^2=14 ?
The solutions to the equation 2(z-1/9)^2=14 are z=sqrt(7)+1/9 ,z=-sqrt(7)+1/9
Find the zeros of 2(z-1/9)^2=14
The zeros of 2(z-1/9)^2=14 are z=sqrt(7)+1/9 ,z=-sqrt(7)+1/9