What are the solutions to the equation x(x+5)-2x=0 ?

The solutions to the equation x(x+5)-2x=0 are x=0,x=-3

Find the zeros of x(x+5)-2x=0

The zeros of x(x+5)-2x=0 are x=0,x=-3

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x (x + 5) - 2 x = 0

x = 0, x = - 3

Solution steps

x (x + 5) - 2 x = 0

Expand

x (x + 5) - 2 x : x^{2} + 3 x

x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 \cdot 1}, x_{2} = \frac{- 3 - 3}{2 \cdot 1}

x = \frac{- 3 + 3}{2 \cdot 1} : 0

x = \frac{- 3 - 3}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 0, x = - 3

4 (x^{2} - 2) - 3 (x^{2} - 1) = 20

x, 36 y^{2} + x^{2} + 36 z = 9

5 x^{2} + 2 x + 6 = 0

x, y^{2} = 12 x^{2}

6 x - 2 x^{2} = 10

What are the solutions to the equation x(x+5)-2x=0 ?
The solutions to the equation x(x+5)-2x=0 are x=0,x=-3
Find the zeros of x(x+5)-2x=0
The zeros of x(x+5)-2x=0 are x=0,x=-3