What are the solutions to the equation factor t^2+8t+16=0 ?

The solutions to the equation factor t^2+8t+16=0 are t=-4

Find the zeros of factor t^2+8t+16=0

The zeros of factor t^2+8t+16=0 are t=-4

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t^{2} + 8 t + 16 = 0

t = - 4

Solution steps

t^{2} + 8 t + 16 = 0

Factor

t^{2} + 8 t + 16 : (t + 4)^{2}

(t + 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t + 4 = 0

Solve

t + 4 = 0 : t = - 4

The solution to the quadratic equation is:

t = - 4

0 = 0.03 q^{2} + 35 q - 712

4 x^{2} - 250 = 0

4 x^{2} - 6 = 2 x

9 = - 4.9 t^{2} + 17.4 t + 2

0 = - 0.02 x^{2} + x + 2.6

What are the solutions to the equation factor t^2+8t+16=0 ?
The solutions to the equation factor t^2+8t+16=0 are t=-4
Find the zeros of factor t^2+8t+16=0
The zeros of factor t^2+8t+16=0 are t=-4