What are the solutions to the equation 0=0.03q^2+35q-712 ?

The solutions to the equation 0=0.03q^2+35q-712 are q=20,q=-3560/3

Find the zeros of 0=0.03q^2+35q-712

The zeros of 0=0.03q^2+35q-712 are q=20,q=-3560/3

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0 = 0.03 q^{2} + 35 q - 712

q = 20, q = - \frac{3560}{3}

Decimal Notation

q = 20, q = - 1186.66666 \dots

Solution steps

0 = 0.03 q^{2} + 35 q - 712

Multiply both sides by

100

0 = 3 q^{2} + 3500 q - 71200

Switch sides

3 q^{2} + 3500 q - 71200 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 3500 \pm 350 0 ^{2} - 4 \cdot 3 ( - 71200 )}{2 \cdot 3}

350 0^{2} - 4 \cdot 3 (- 71200) = 3620

q_{1, 2} = \frac{- 3500 \pm 3620}{2 \cdot 3}

Separate the solutions

q_{1} = \frac{- 3500 + 3620}{2 \cdot 3}, q_{2} = \frac{- 3500 - 3620}{2 \cdot 3}

q = \frac{- 3500 + 3620}{2 \cdot 3} : 20

q = \frac{- 3500 - 3620}{2 \cdot 3} : - \frac{3560}{3}

The solutions to the quadratic equation are:

q = 20, q = - \frac{3560}{3}

4 x^{2} - 250 = 0

4 x^{2} - 6 = 2 x

9 = - 4.9 t^{2} + 17.4 t + 2

0 = - 0.02 x^{2} + x + 2.6

(x - 6) (x - 1) = 4 x - 18

What are the solutions to the equation 0=0.03q^2+35q-712 ?
The solutions to the equation 0=0.03q^2+35q-712 are q=20,q=-3560/3
Find the zeros of 0=0.03q^2+35q-712
The zeros of 0=0.03q^2+35q-712 are q=20,q=-3560/3