What are the solutions to the equation 9=-4.9t^2+17.4t+2 ?

The solutions to the equation 9=-4.9t^2+17.4t+2 are t=(87-sqrt(4139))/(49),t=(87+sqrt(4139))/(49)

Find the zeros of 9=-4.9t^2+17.4t+2

The zeros of 9=-4.9t^2+17.4t+2 are t=(87-sqrt(4139))/(49),t=(87+sqrt(4139))/(49)

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9 = - 4.9 t^{2} + 17.4 t + 2

t = \frac{87 - 4139}{49}, t = \frac{87 + 4139}{49}

Decimal Notation

t = 0.46254 \dots, t = 3.08847 \dots

Solution steps

9 = - 4.9 t^{2} + 17.4 t + 2

Multiply both sides by

10

90 = - 49 t^{2} + 174 t + 20

Switch sides

- 49 t^{2} + 174 t + 20 = 90

Move

90

to the left side

- 49 t^{2} + 174 t - 70 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 174 \pm 17 4 ^{2} - 4 ( - 49 ) ( - 70 )}{2 ( - 49 )}

17 4^{2} - 4 (- 49) (- 70) = 24139

t_{1, 2} = \frac{- 174 \pm 2 4139}{2 ( - 49 )}

Separate the solutions

t_{1} = \frac{- 174 + 2 4139}{2 ( - 49 )}, t_{2} = \frac{- 174 - 2 4139}{2 ( - 49 )}

t = \frac{- 174 + 2 4139}{2 ( - 49 )} : \frac{87 - 4139}{49}

t = \frac{- 174 - 2 4139}{2 ( - 49 )} : \frac{87 + 4139}{49}

The solutions to the quadratic equation are:

t = \frac{87 - 4139}{49}, t = \frac{87 + 4139}{49}

0 = - 0.02 x^{2} + x + 2.6

(x - 6) (x - 1) = 4 x - 18

k^{2} - 3 k - 4 = 0

(x + 3)^{2} = 3 - x

x^{2} + 14 x + 64 = 0

What are the solutions to the equation 9=-4.9t^2+17.4t+2 ?
The solutions to the equation 9=-4.9t^2+17.4t+2 are t=(87-sqrt(4139))/(49),t=(87+sqrt(4139))/(49)
Find the zeros of 9=-4.9t^2+17.4t+2
The zeros of 9=-4.9t^2+17.4t+2 are t=(87-sqrt(4139))/(49),t=(87+sqrt(4139))/(49)