What are the solutions to the equation (x-4)^2-25=12 ?

The solutions to the equation (x-4)^2-25=12 are x=sqrt(37)+4,x=-sqrt(37)+4

Find the zeros of (x-4)^2-25=12

The zeros of (x-4)^2-25=12 are x=sqrt(37)+4,x=-sqrt(37)+4

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(x - 4)^{2} - 25 = 12

x = 37 + 4, x = - 37 + 4

Decimal Notation

x = 10.08276 \dots, x = - 2.08276 \dots

Solution steps

(x - 4)^{2} - 25 = 12

Move

25

to the right side

(x - 4)^{2} = 37

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 37 : x = 37 + 4

Solve

x - 4 = - 37 : x = - 37 + 4

The solutions to the quadratic equation are:

x = 37 + 4, x = - 37 + 4

(x + 7)^{2} - 288 = 0

5 x^{2} - 23 x = - 12

4 x^{2} - 4 x + 7 x - 7 = 2

8 x + 2 + 5 x^{2} = 4

2 x (9 - 5 x) = - 5 x (2 - 3 x)

What are the solutions to the equation (x-4)^2-25=12 ?
The solutions to the equation (x-4)^2-25=12 are x=sqrt(37)+4,x=-sqrt(37)+4
Find the zeros of (x-4)^2-25=12
The zeros of (x-4)^2-25=12 are x=sqrt(37)+4,x=-sqrt(37)+4