What are the solutions to the equation p^2+13p+19=0 ?

The solutions to the equation p^2+13p+19=0 are p=(-13+sqrt(93))/2 ,p=(-13-sqrt(93))/2

Find the zeros of p^2+13p+19=0

The zeros of p^2+13p+19=0 are p=(-13+sqrt(93))/2 ,p=(-13-sqrt(93))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

p^{2} + 13 p + 19 = 0

p = \frac{- 13 + 93}{2}, p = \frac{- 13 - 93}{2}

Decimal Notation

p = - 1.67817 \dots, p = - 11.32182 \dots

Solution steps

p^{2} + 13 p + 19 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot 19 = 93

p_{1, 2} = \frac{- 13 \pm 93}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 13 + 93}{2 \cdot 1}, p_{2} = \frac{- 13 - 93}{2 \cdot 1}

p = \frac{- 13 + 93}{2 \cdot 1} : \frac{- 13 + 93}{2}

p = \frac{- 13 - 93}{2 \cdot 1} : \frac{- 13 - 93}{2}

The solutions to the quadratic equation are:

p = \frac{- 13 + 93}{2}, p = \frac{- 13 - 93}{2}

x (x + 6) = 8 + 4 x

x^{2} = \frac{- 7 x - 3}{2}

2 q^{2} + 9 q + 3 = 4

2 x (x + 4) = (x - 3)^{2}

x (x + 3) = 16

What are the solutions to the equation p^2+13p+19=0 ?
The solutions to the equation p^2+13p+19=0 are p=(-13+sqrt(93))/2 ,p=(-13-sqrt(93))/2
Find the zeros of p^2+13p+19=0
The zeros of p^2+13p+19=0 are p=(-13+sqrt(93))/2 ,p=(-13-sqrt(93))/2