What are the solutions to the equation x^2-2x+3=75 ?

The solutions to the equation x^2-2x+3=75 are x=1+sqrt(73),x=1-sqrt(73)

Find the zeros of x^2-2x+3=75

The zeros of x^2-2x+3=75 are x=1+sqrt(73),x=1-sqrt(73)

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x^{2} - 2 x + 3 = 75

x = 1 + 73, x = 1 - 73

Decimal Notation

x = 9.54400 \dots, x = - 7.54400 \dots

Solution steps

x^{2} - 2 x + 3 = 75

Move

75

to the left side

x^{2} - 2 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 72) = 273

x_{1, 2} = \frac{- ( - 2 ) \pm 2 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 73}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 73}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 73}{2 \cdot 1} : 1 + 73

x = \frac{- ( - 2 ) - 2 73}{2 \cdot 1} : 1 - 73

The solutions to the quadratic equation are:

x = 1 + 73, x = 1 - 73

2 x^{2} + 7 x = - 4

x^{2} + a x = 20 a^{2}

x^{2} - 4 x + 61 = 10 x + 13

x, 5 x y - x^{2} y + y^{2} = 0

x^{2} + 4 x + 1 + 5 = 0

What are the solutions to the equation x^2-2x+3=75 ?
The solutions to the equation x^2-2x+3=75 are x=1+sqrt(73),x=1-sqrt(73)
Find the zeros of x^2-2x+3=75
The zeros of x^2-2x+3=75 are x=1+sqrt(73),x=1-sqrt(73)