What are the solutions to the equation 6x^2+2x-18=0 ?

The solutions to the equation 6x^2+2x-18=0 are x=(-1+sqrt(109))/6 ,x=-(1+sqrt(109))/6

Find the zeros of 6x^2+2x-18=0

The zeros of 6x^2+2x-18=0 are x=(-1+sqrt(109))/6 ,x=-(1+sqrt(109))/6

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6 x^{2} + 2 x - 18 = 0

x = \frac{- 1 + 109}{6}, x = - \frac{1 + 109}{6}

Decimal Notation

x = 1.57338 \dots, x = - 1.90671 \dots

Solution steps

6 x^{2} + 2 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 ( - 18 )}{2 \cdot 6}

2^{2} - 4 \cdot 6 (- 18) = 2109

x_{1, 2} = \frac{- 2 \pm 2 109}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 2 + 2 109}{2 \cdot 6}, x_{2} = \frac{- 2 - 2 109}{2 \cdot 6}

x = \frac{- 2 + 2 109}{2 \cdot 6} : \frac{- 1 + 109}{6}

x = \frac{- 2 - 2 109}{2 \cdot 6} : - \frac{1 + 109}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 109}{6}, x = - \frac{1 + 109}{6}

16 x^{2} - 4 = 4 x^{2} + \frac{3}{4}

2 x^{2} - 8 x + 13

x^{2} - 6 x = - 10 x + 12

2 (x - 3)^{2} - 72 = 0

3 k^{2} - 14 k - 21 = 0

What are the solutions to the equation 6x^2+2x-18=0 ?
The solutions to the equation 6x^2+2x-18=0 are x=(-1+sqrt(109))/6 ,x=-(1+sqrt(109))/6
Find the zeros of 6x^2+2x-18=0
The zeros of 6x^2+2x-18=0 are x=(-1+sqrt(109))/6 ,x=-(1+sqrt(109))/6