What are the solutions to the equation 28x-49x^2=4 ?

The solutions to the equation 28x-49x^2=4 are x= 2/7

Find the zeros of 28x-49x^2=4

The zeros of 28x-49x^2=4 are x= 2/7

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28 x - 49 x^{2} = 4

x = \frac{2}{7}

Decimal Notation

x = 0.28571 \dots

Solution steps

28 x - 49 x^{2} = 4

Move

4

to the left side

28 x - 49 x^{2} - 4 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 49 x^{2} + 28 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 ( - 49 ) ( - 4 )}{2 ( - 49 )}

2 8^{2} - 4 (- 49) (- 4) = 0

x_{1, 2} = \frac{- 28 \pm 0}{2 ( - 49 )}

x = \frac{- 28}{2 ( - 49 )}

\frac{- 28}{2 ( - 49 )} = \frac{2}{7}

x = \frac{2}{7}

The solution to the quadratic equation is:

x = \frac{2}{7}

3 x^{2} + 12 x - 9

x, 9 x^{2} - m^{2} = 0

t^{2} - 6 t + 13 = 0

2 m^{2} + 7 m - 4 = 0

y^{2} + 3 y - 1

What are the solutions to the equation 28x-49x^2=4 ?
The solutions to the equation 28x-49x^2=4 are x= 2/7
Find the zeros of 28x-49x^2=4
The zeros of 28x-49x^2=4 are x= 2/7