What are the solutions to the equation (2x-1)^{(2)}-5(2x-1)-6=0 ?

The solutions to the equation (2x-1)^{(2)}-5(2x-1)-6=0 are x= 7/2 ,x=0

Find the zeros of (2x-1)^{(2)}-5(2x-1)-6=0

The zeros of (2x-1)^{(2)}-5(2x-1)-6=0 are x= 7/2 ,x=0

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(2 x - 1)^{(2)} - 5 (2 x - 1) - 6 = 0

x = \frac{7}{2}, x = 0

Decimal Notation

x = 3.5, x = 0

Solution steps

(2 x - 1)^{(2)} - 5 (2 x - 1) - 6 = 0

Expand

(2 x - 1)^{2} - 5 (2 x - 1) - 6 : 4 x^{2} - 14 x

4 x^{2} - 14 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 14)^{2} - 4 \cdot 4 \cdot 0 = 14

x_{1, 2} = \frac{- ( - 14 ) \pm 14}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 14}{2 \cdot 4}, x_{2} = \frac{- ( - 14 ) - 14}{2 \cdot 4}

x = \frac{- ( - 14 ) + 14}{2 \cdot 4} : \frac{7}{2}

x = \frac{- ( - 14 ) - 14}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = 0

- 6 = (2 x - 4)^{2} - 10

(7 x + 4)^{2} = 48

3 x^{2} + 5 x = 7 (x^{2} + x)

5 x^{2} + 40 x - 410 = 0

y, y^{2} - y - x^{2} = 0

What are the solutions to the equation (2x-1)^{(2)}-5(2x-1)-6=0 ?
The solutions to the equation (2x-1)^{(2)}-5(2x-1)-6=0 are x= 7/2 ,x=0
Find the zeros of (2x-1)^{(2)}-5(2x-1)-6=0
The zeros of (2x-1)^{(2)}-5(2x-1)-6=0 are x= 7/2 ,x=0