What are the solutions to the equation 2b^2+5b-2=6b ?

The solutions to the equation 2b^2+5b-2=6b are b=(1+sqrt(17))/4 ,b=(1-sqrt(17))/4

Find the zeros of 2b^2+5b-2=6b

The zeros of 2b^2+5b-2=6b are b=(1+sqrt(17))/4 ,b=(1-sqrt(17))/4

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2 b^{2} + 5 b - 2 = 6 b

b = \frac{1 + 17}{4}, b = \frac{1 - 17}{4}

Decimal Notation

b = 1.28077 \dots, b = - 0.78077 \dots

Solution steps

2 b^{2} + 5 b - 2 = 6 b

Move

6 b

to the left side

2 b^{2} - b - 2 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 2) = 17

b_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 2}

Separate the solutions

b_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 2}, b_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 2}

b = \frac{- ( - 1 ) + 17}{2 \cdot 2} : \frac{1 + 17}{4}

b = \frac{- ( - 1 ) - 17}{2 \cdot 2} : \frac{1 - 17}{4}

The solutions to the quadratic equation are:

b = \frac{1 + 17}{4}, b = \frac{1 - 17}{4}

4 x^{2} - 4 + 5 x = 0

3 x^{2} = 39 x

(x + 1)^{2} - 7 (x + 1) + 10 = 0

x^{2} + 35 = 12 x

x, \frac{2 x ^{2}}{3} = d g

What are the solutions to the equation 2b^2+5b-2=6b ?
The solutions to the equation 2b^2+5b-2=6b are b=(1+sqrt(17))/4 ,b=(1-sqrt(17))/4
Find the zeros of 2b^2+5b-2=6b
The zeros of 2b^2+5b-2=6b are b=(1+sqrt(17))/4 ,b=(1-sqrt(17))/4