What are the solutions to the equation 15c^2-8c-12=0 ?

The solutions to the equation 15c^2-8c-12=0 are c= 6/5 ,c=-2/3

Find the zeros of 15c^2-8c-12=0

The zeros of 15c^2-8c-12=0 are c= 6/5 ,c=-2/3

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15 c^{2} - 8 c - 12 = 0

c = \frac{6}{5}, c = - \frac{2}{3}

Decimal Notation

c = 1.2, c = - 0.66666 \dots

Solution steps

15 c^{2} - 8 c - 12 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 15 ( - 12 )}{2 \cdot 15}

(- 8)^{2} - 4 \cdot 15 (- 12) = 28

c_{1, 2} = \frac{- ( - 8 ) \pm 28}{2 \cdot 15}

Separate the solutions

c_{1} = \frac{- ( - 8 ) + 28}{2 \cdot 15}, c_{2} = \frac{- ( - 8 ) - 28}{2 \cdot 15}

c = \frac{- ( - 8 ) + 28}{2 \cdot 15} : \frac{6}{5}

c = \frac{- ( - 8 ) - 28}{2 \cdot 15} : - \frac{2}{3}

The solutions to the quadratic equation are:

c = \frac{6}{5}, c = - \frac{2}{3}

- 3 x^{2} + 15 x - 18 = 0

21 x^{2} - 13 - 20 = 0

\frac{1}{2} x^{2} + 3 x = 8

x^{2} + 12 x = - 21

m (m - 7) = - 10

What are the solutions to the equation 15c^2-8c-12=0 ?
The solutions to the equation 15c^2-8c-12=0 are c= 6/5 ,c=-2/3
Find the zeros of 15c^2-8c-12=0
The zeros of 15c^2-8c-12=0 are c= 6/5 ,c=-2/3