What are the solutions to the equation 2x^2=7x+15 ?

The solutions to the equation 2x^2=7x+15 are x=5,x=-3/2

Find the zeros of 2x^2=7x+15

The zeros of 2x^2=7x+15 are x=5,x=-3/2

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2 x^{2} = 7 x + 15

x = 5, x = - \frac{3}{2}

Decimal Notation

x = 5, x = - 1.5

Solution steps

2 x^{2} = 7 x + 15

Move

15

to the left side

2 x^{2} - 15 = 7 x

Move

7 x

to the left side

2 x^{2} - 15 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 7 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 15) = 13

x_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 2}

x = \frac{- ( - 7 ) + 13}{2 \cdot 2} : 5

x = \frac{- ( - 7 ) - 13}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 5, x = - \frac{3}{2}

9 = π + r^{2} 16

2 x^{2} = x + 8

(x + 4)^{2} = 31

(5 p + 2)^{2} = 8

c^{2} - 7 c + 12 = 0

What are the solutions to the equation 2x^2=7x+15 ?
The solutions to the equation 2x^2=7x+15 are x=5,x=-3/2
Find the zeros of 2x^2=7x+15
The zeros of 2x^2=7x+15 are x=5,x=-3/2