What are the solutions to the equation 1/4 x^2+36x=0 ?

The solutions to the equation 1/4 x^2+36x=0 are x=0,x=-144

Find the zeros of 1/4 x^2+36x=0

The zeros of 1/4 x^2+36x=0 are x=0,x=-144

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\frac{1}{4} x^{2} + 36 x = 0

x = 0, x = - 144

Solution steps

\frac{1}{4} x^{2} + 36 x = 0

Multiply both sides by

4

x^{2} + 144 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 144 \pm 14 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

14 4^{2} - 4 \cdot 1 \cdot 0 = 144

x_{1, 2} = \frac{- 144 \pm 144}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 144 + 144}{2 \cdot 1}, x_{2} = \frac{- 144 - 144}{2 \cdot 1}

x = \frac{- 144 + 144}{2 \cdot 1} : 0

x = \frac{- 144 - 144}{2 \cdot 1} : - 144

The solutions to the quadratic equation are:

x = 0, x = - 144

15 x^{2} = 12

- 80 = x (x - 16)

(x + 5) (x - 9) = 21

(2 x + 7)^{2} + 3 = 52

- 7 x^{2} - 8 x + 24 = 0

What are the solutions to the equation 1/4 x^2+36x=0 ?
The solutions to the equation 1/4 x^2+36x=0 are x=0,x=-144
Find the zeros of 1/4 x^2+36x=0
The zeros of 1/4 x^2+36x=0 are x=0,x=-144