What are the solutions to the equation -80=x(x-16) ?

The solutions to the equation -80=x(x-16) are x=8+4i,x=8-4i

Find the zeros of -80=x(x-16)

The zeros of -80=x(x-16) are x=8+4i,x=8-4i

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- 80 = x (x - 16)

x = 8 + 4 i, x = 8 - 4 i

Solution steps

- 80 = x (x - 16)

Expand

x (x - 16) : x^{2} - 16 x

- 80 = x^{2} - 16 x

Switch sides

x^{2} - 16 x = - 80

Move

80

to the left side

x^{2} - 16 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 80}{2 \cdot 1}

Simplify

(- 16)^{2} - 4 \cdot 1 \cdot 80 : 8 i

x_{1, 2} = \frac{- ( - 16 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 8 i}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 8 i}{2 \cdot 1}

x = \frac{- ( - 16 ) + 8 i}{2 \cdot 1} : 8 + 4 i

x = \frac{- ( - 16 ) - 8 i}{2 \cdot 1} : 8 - 4 i

The solutions to the quadratic equation are:

x = 8 + 4 i, x = 8 - 4 i

(x + 5) (x - 9) = 21

(2 x + 7)^{2} + 3 = 52

- 7 x^{2} - 8 x + 24 = 0

6 x^{2} + 3 x - 7 = 0

2 x^{2} + 9 x = 10

What are the solutions to the equation -80=x(x-16) ?
The solutions to the equation -80=x(x-16) are x=8+4i,x=8-4i
Find the zeros of -80=x(x-16)
The zeros of -80=x(x-16) are x=8+4i,x=8-4i