What are the solutions to the equation (2x+7)^2+3=52 ?

The solutions to the equation (2x+7)^2+3=52 are x=0,x=-7

Find the zeros of (2x+7)^2+3=52

The zeros of (2x+7)^2+3=52 are x=0,x=-7

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(2 x + 7)^{2} + 3 = 52

x = 0, x = - 7

Solution steps

(2 x + 7)^{2} + 3 = 52

Move

3

to the right side

(2 x + 7)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 7 = 49 : x = 0

Solve

2 x + 7 = - 49 : x = - 7

The solutions to the quadratic equation are:

x = 0, x = - 7

- 7 x^{2} - 8 x + 24 = 0

6 x^{2} + 3 x - 7 = 0

2 x^{2} + 9 x = 10

(2 x + 1)^{2} = 121

0 = 2 x^{2} - 4

What are the solutions to the equation (2x+7)^2+3=52 ?
The solutions to the equation (2x+7)^2+3=52 are x=0,x=-7
Find the zeros of (2x+7)^2+3=52
The zeros of (2x+7)^2+3=52 are x=0,x=-7