What are the solutions to the equation s^2+4s+9=0 ?

The solutions to the equation s^2+4s+9=0 are s=-2+sqrt(5)i,s=-2-sqrt(5)i

Find the zeros of s^2+4s+9=0

The zeros of s^2+4s+9=0 are s=-2+sqrt(5)i,s=-2-sqrt(5)i

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s^{2} + 4 s + 9 = 0

s = - 2 + 5 i, s = - 2 - 5 i

Solution steps

s^{2} + 4 s + 9 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 9 : 25 i

s_{1, 2} = \frac{- 4 \pm 2 5 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 4 + 2 5 i}{2 \cdot 1}, s_{2} = \frac{- 4 - 2 5 i}{2 \cdot 1}

s = \frac{- 4 + 2 5 i}{2 \cdot 1} : - 2 + 5 i

s = \frac{- 4 - 2 5 i}{2 \cdot 1} : - 2 - 5 i

The solutions to the quadratic equation are:

s = - 2 + 5 i, s = - 2 - 5 i

x^{2} + 5 x + 2 = - 4

\frac{( x - 2 ) ^{2}}{2} = x + 2

x^{2} - 2 x + 4 = 0

4 a^{2} + 6 = 106

0 = 8 - 9 x^{2} + 13 x

What are the solutions to the equation s^2+4s+9=0 ?
The solutions to the equation s^2+4s+9=0 are s=-2+sqrt(5)i,s=-2-sqrt(5)i
Find the zeros of s^2+4s+9=0
The zeros of s^2+4s+9=0 are s=-2+sqrt(5)i,s=-2-sqrt(5)i