What are the solutions to the equation 3(x+7)^2=48 ?

The solutions to the equation 3(x+7)^2=48 are x=-3,x=-11

Find the zeros of 3(x+7)^2=48

The zeros of 3(x+7)^2=48 are x=-3,x=-11

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3 (x + 7)^{2} = 48

x = - 3, x = - 11

Solution steps

3 (x + 7)^{2} = 48

Divide both sides by

3

(x + 7)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 16 : x = - 3

Solve

x + 7 = - 16 : x = - 11

The solutions to the quadratic equation are:

x = - 3, x = - 11

7 x^{2} + 25 x - 12 = 0

- x^{2} + 3 x = - 4

2 x^{2} + 7 x 3 + 9 = 0

8 x^{2} = 7 - 10 x

2 x^{2} = \frac{1}{2}

What are the solutions to the equation 3(x+7)^2=48 ?
The solutions to the equation 3(x+7)^2=48 are x=-3,x=-11
Find the zeros of 3(x+7)^2=48
The zeros of 3(x+7)^2=48 are x=-3,x=-11