What are the solutions to the equation 0=100+87*t-5*t^2 ?

The solutions to the equation 0=100+87*t-5*t^2 are t=-(-87+sqrt(9569))/(10),t=(87+sqrt(9569))/(10)

Find the zeros of 0=100+87*t-5*t^2

The zeros of 0=100+87*t-5*t^2 are t=-(-87+sqrt(9569))/(10),t=(87+sqrt(9569))/(10)

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0 = 100 + 87 \cdot t - 5 \cdot t^{2}

t = - \frac{- 87 + 9569}{10}, t = \frac{87 + 9569}{10}

Decimal Notation

t = - 1.08212 \dots, t = 18.48212 \dots

Solution steps

0 = 100 + 87 t - 5 t^{2}

Switch sides

100 + 87 t - 5 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 t^{2} + 87 t + 100 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 87 \pm 8 7 ^{2} - 4 ( - 5 ) \cdot 100}{2 ( - 5 )}

8 7^{2} - 4 (- 5) \cdot 100 = 9569

t_{1, 2} = \frac{- 87 \pm 9569}{2 ( - 5 )}

Separate the solutions

t_{1} = \frac{- 87 + 9569}{2 ( - 5 )}, t_{2} = \frac{- 87 - 9569}{2 ( - 5 )}

t = \frac{- 87 + 9569}{2 ( - 5 )} : - \frac{- 87 + 9569}{10}

t = \frac{- 87 - 9569}{2 ( - 5 )} : \frac{87 + 9569}{10}

The solutions to the quadratic equation are:

t = - \frac{- 87 + 9569}{10}, t = \frac{87 + 9569}{10}

- 6 x^{2} = - x - 2

(x + 2) (3 x) = (x + 2) (6)

2 x^{2} + x = x^{2} + 20

(x - 4)^{2} = - 2

(2 y - 5)^{2} = 0

What are the solutions to the equation 0=100+87*t-5*t^2 ?
The solutions to the equation 0=100+87*t-5*t^2 are t=-(-87+sqrt(9569))/(10),t=(87+sqrt(9569))/(10)
Find the zeros of 0=100+87*t-5*t^2
The zeros of 0=100+87*t-5*t^2 are t=-(-87+sqrt(9569))/(10),t=(87+sqrt(9569))/(10)