What are the solutions to the equation 2x^2-12x=-3 ?

The solutions to the equation 2x^2-12x=-3 are x=(6+sqrt(30))/2 ,x=(6-sqrt(30))/2

Find the zeros of 2x^2-12x=-3

The zeros of 2x^2-12x=-3 are x=(6+sqrt(30))/2 ,x=(6-sqrt(30))/2

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2 x^{2} - 12 x = - 3

x = \frac{6 + 30}{2}, x = \frac{6 - 30}{2}

Decimal Notation

x = 5.73861 \dots, x = 0.26138 \dots

Solution steps

2 x^{2} - 12 x = - 3

Move

3

to the left side

2 x^{2} - 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 \cdot 3 = 230

x_{1, 2} = \frac{- ( - 12 ) \pm 2 30}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 30}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 2 30}{2 \cdot 2}

x = \frac{- ( - 12 ) + 2 30}{2 \cdot 2} : \frac{6 + 30}{2}

x = \frac{- ( - 12 ) - 2 30}{2 \cdot 2} : \frac{6 - 30}{2}

The solutions to the quadratic equation are:

x = \frac{6 + 30}{2}, x = \frac{6 - 30}{2}

x^{2} + 7 x + 21 = 0

5 x^{2} - 1 = 7 x

- 7 - 4 (x + 3)^{2} = - 71

(x - 9) = x^{2} - 81

x (x + 8) = 16 (x - 1)

What are the solutions to the equation 2x^2-12x=-3 ?
The solutions to the equation 2x^2-12x=-3 are x=(6+sqrt(30))/2 ,x=(6-sqrt(30))/2
Find the zeros of 2x^2-12x=-3
The zeros of 2x^2-12x=-3 are x=(6+sqrt(30))/2 ,x=(6-sqrt(30))/2