What are the solutions to the equation x(x+8)=16(x-1) ?

The solutions to the equation x(x+8)=16(x-1) are x=4

Find the zeros of x(x+8)=16(x-1)

The zeros of x(x+8)=16(x-1) are x=4

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x (x + 8) = 16 (x - 1)

x = 4

Solution steps

x (x + 8) = 16 (x - 1)

Expand

x (x + 8) : x^{2} + 8 x

Expand

16 (x - 1) : 16 x - 16

x^{2} + 8 x = 16 x - 16

Move

16

to the left side

x^{2} + 8 x + 16 = 16 x

Move

16 x

to the left side

x^{2} - 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

x = 4

The solution to the quadratic equation is:

x = 4

- 3 c^{2} + 6 c = 0

\frac{5}{2} x^{2} - 4 x + 2 = 0

x^{2} + 175 = 0

x^{2} + 15 x - 8 = 0

2 x (x - 5) + 2 = 3 x

What are the solutions to the equation x(x+8)=16(x-1) ?
The solutions to the equation x(x+8)=16(x-1) are x=4
Find the zeros of x(x+8)=16(x-1)
The zeros of x(x+8)=16(x-1) are x=4