What are the solutions to the equation -7-4(x+3)^2=-71 ?

The solutions to the equation -7-4(x+3)^2=-71 are x=1,x=-7

Find the zeros of -7-4(x+3)^2=-71

The zeros of -7-4(x+3)^2=-71 are x=1,x=-7

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- 7 - 4 (x + 3)^{2} = - 71

x = 1, x = - 7

Solution steps

- 7 - 4 (x + 3)^{2} = - 71

Move

7

to the right side

- 4 (x + 3)^{2} = - 64

Divide both sides by

- 4

(x + 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 16 : x = 1

Solve

x + 3 = - 16 : x = - 7

The solutions to the quadratic equation are:

x = 1, x = - 7

(x - 9) = x^{2} - 81

x (x + 8) = 16 (x - 1)

- 3 c^{2} + 6 c = 0

\frac{5}{2} x^{2} - 4 x + 2 = 0

x^{2} + 175 = 0

What are the solutions to the equation -7-4(x+3)^2=-71 ?
The solutions to the equation -7-4(x+3)^2=-71 are x=1,x=-7
Find the zeros of -7-4(x+3)^2=-71
The zeros of -7-4(x+3)^2=-71 are x=1,x=-7