What are the solutions to the equation (x-3)(x-1)=8 ?

The solutions to the equation (x-3)(x-1)=8 are x=5,x=-1

Find the zeros of (x-3)(x-1)=8

The zeros of (x-3)(x-1)=8 are x=5,x=-1

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(x - 3) (x - 1) = 8

x = 5, x = - 1

Solution steps

(x - 3) (x - 1) = 8

Expand

(x - 3) (x - 1) : x^{2} - 4 x + 3

x^{2} - 4 x + 3 = 8

Move

8

to the left side

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

5 x^{2} = 17

- 4 x^{2} + x - 25 = - 3 x^{2} + 17 x + 38

(3 y - 1) (y + 2) = 0

(x + 7)^{2} + 7 (x + 7) + 12 = 0

(4 x + 4) (a x - 1) - x^{2} + 4 = b x

What are the solutions to the equation (x-3)(x-1)=8 ?
The solutions to the equation (x-3)(x-1)=8 are x=5,x=-1
Find the zeros of (x-3)(x-1)=8
The zeros of (x-3)(x-1)=8 are x=5,x=-1