What are the solutions to the equation -2x^2-x+4=0 ?

The solutions to the equation -2x^2-x+4=0 are x=-(1+sqrt(33))/4 ,x=(sqrt(33)-1)/4

Find the zeros of -2x^2-x+4=0

The zeros of -2x^2-x+4=0 are x=-(1+sqrt(33))/4 ,x=(sqrt(33)-1)/4

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- 2 x^{2} - x + 4 = 0

x = - \frac{1 + 33}{4}, x = \frac{33 - 1}{4}

Decimal Notation

x = - 1.68614 \dots, x = 1.18614 \dots

Solution steps

- 2 x^{2} - x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 2 ) \cdot 4}{2 ( - 2 )}

(- 1)^{2} - 4 (- 2) \cdot 4 = 33

x_{1, 2} = \frac{- ( - 1 ) \pm 33}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 33}{2 ( - 2 )}, x_{2} = \frac{- ( - 1 ) - 33}{2 ( - 2 )}

x = \frac{- ( - 1 ) + 33}{2 ( - 2 )} : - \frac{1 + 33}{4}

x = \frac{- ( - 1 ) - 33}{2 ( - 2 )} : \frac{33 - 1}{4}

The solutions to the quadratic equation are:

x = - \frac{1 + 33}{4}, x = \frac{33 - 1}{4}

(2 + 3 x)^{2} = (1 - x) (1 + x)

2 x^{2} - 5 = - 9 x

x, x^{2} + x y + y^{2} - 4 = 0

2 y^{2} + 7 y - 4 = 0

x^{2} - 4 b = 0

What are the solutions to the equation -2x^2-x+4=0 ?
The solutions to the equation -2x^2-x+4=0 are x=-(1+sqrt(33))/4 ,x=(sqrt(33)-1)/4
Find the zeros of -2x^2-x+4=0
The zeros of -2x^2-x+4=0 are x=-(1+sqrt(33))/4 ,x=(sqrt(33)-1)/4