What are the solutions to the equation x^2-4b=0 ?

The solutions to the equation x^2-4b=0 are x=2sqrt(b),x=-2sqrt(b)

Find the zeros of x^2-4b=0

The zeros of x^2-4b=0 are x=2sqrt(b),x=-2sqrt(b)

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x^{2} - 4 b = 0

x = 2 b, x = - 2 b

Solution steps

x^{2} - 4 b = 0

Move

4 b

to the right side

x^{2} = 4 b

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4 b, x = - 4 b

Simplify

4 b : 2 b

Simplify

- 4 b : - 2 b

x = 2 b, x = - 2 b

2 t^{2} - 8 t = - 3

3 x^{2} - 18 x + 1

5 w^{2} - 36 w = 32

2 x^{2} + 32 x + 244 = - 12

- x^{2} + 10 = 4 x + 2

What are the solutions to the equation x^2-4b=0 ?
The solutions to the equation x^2-4b=0 are x=2sqrt(b),x=-2sqrt(b)
Find the zeros of x^2-4b=0
The zeros of x^2-4b=0 are x=2sqrt(b),x=-2sqrt(b)